What is the answer to 9^x+3^{1+2x}=50 ?

The answer to 9^x+3^{1+2x}=50 is x=(ln(25/2))/(2ln(3))

Solve for x: 9^x+3^{1+2x}=50

The solution is x=(ln(25/2))/(2ln(3))

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9^{x} + 3^{1 + 2 x} = 50

x = \frac{ln ( \frac{25}{2} )}{2 ln ( 3 )}

Decimal Notation

x = 1.14950 \dots

Solution steps

9^{x} + 3^{1 + 2 x} = 50

Apply exponent rules

2 x ln (3) = ln (\frac{25}{2})

Solve

2 x ln (3) = ln (\frac{25}{2}) : x = \frac{ln ( \frac{25}{2} )}{2 ln ( 3 )}

x = \frac{ln ( \frac{25}{2} )}{2 ln ( 3 )}

9^{2 x + 5} = 2 7^{x}

4^{3 x - 1} = 3 2^{x}

- 11 e^{- x} = 0

3^{2 x - 1} - 2^{x} = 0

144 \cdot 2^{\frac{x}{3}} = 16

What is the answer to 9^x+3^{1+2x}=50 ?
The answer to 9^x+3^{1+2x}=50 is x=(ln(25/2))/(2ln(3))
Solve for x: 9^x+3^{1+2x}=50
The solution is x=(ln(25/2))/(2ln(3))