What is the answer to 3*9^{2n}=(3^{n+1})^3 ?

The answer to 3*9^{2n}=(3^{n+1})^3 is n=2

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3*9^{2n}=(3^{n+1})^3

3 \cdot 9^{2 n} = (3^{n + 1})^{3}

n = 2

Solution steps

3 \cdot 9^{2 n} = (3^{n + 1})^{3}

Apply exponent rules

4 n + 1 = (n + 1) \cdot 3

Solve

4 n + 1 = (n + 1) \cdot 3 : n = 2

n = 2

- x e^{- x} + 7 e^{- x} = 0

8^{x + 1} = 128

e^{3 x} + 2 e^{x} - 3 e^{2 x} = 0

2^{3 x + 2} = 1 6^{3 x - 4}

\frac{5}{1 + e ^{- x}} = 4

What is the answer to 3*9^{2n}=(3^{n+1})^3 ?
The answer to 3*9^{2n}=(3^{n+1})^3 is n=2
Solve for n: 3*9^{2n}=(3^{n+1})^3
The solution is n=2