What is the answer to (27^x)/(9^{2x-1)}=3^{x+4} ?

The answer to (27^x)/(9^{2x-1)}=3^{x+4} is x=-1

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(27^x)/(9^{2x-1)}=3^{x+4}

\frac{2 7 ^{x}}{9 ^{2 x - 1}} = 3^{x + 4}

x = - 1

Solution steps

\frac{2 7 ^{x}}{9 ^{2 x - 1}} = 3^{x + 4}

Apply exponent rules

3 x + 2 (- 2 x + 1) = x + 4

Solve

3 x + 2 (- 2 x + 1) = x + 4 : x = - 1

x = - 1

Verify Solutions:

x = - 1

True

The solution is

x = - 1

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x, 3 6^{x + 1} = 6

8^{x} = 128

What is the answer to (27^x)/(9^{2x-1)}=3^{x+4} ?
The answer to (27^x)/(9^{2x-1)}=3^{x+4} is x=-1
Solve for x: (27^x)/(9^{2x-1)}=3^{x+4}
The solution is x=-1