What is the answer to 2\times 3^x+5\times 3^x-3^x=6 ?

The answer to 2\times 3^x+5\times 3^x-3^x=6 is x=0

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2\times 3^x+5\times 3^x-3^x=6

2 \cdot 3^{x} + 5 \cdot 3^{x} - 3^{x} = 6

x = 0

Solution steps

2 \cdot 3^{x} + 5 \cdot 3^{x} - 3^{x} = 6

Add similar elements:

2 \cdot 3^{x} + 5 \cdot 3^{x} - 3^{x} = 6 \cdot 3^{x}

6 \cdot 3^{x} = 6

Divide both sides by

6

3^{x} = 1

Apply exponent rules

x ln (3) = ln (1)

Solve

x ln (3) = ln (1) : x = 0

x = 0

8^{9 - x} = 6 4^{x}

e^{8 x} + 8 e^{8 x} x = 0

125 = 2 5^{2 h + 1}

2^{(1 + 2 x)} = 32

y, 2^{x} + 3^{y} = 5

What is the answer to 2\times 3^x+5\times 3^x-3^x=6 ?
The answer to 2\times 3^x+5\times 3^x-3^x=6 is x=0
Solve for x: 2\times 3^x+5\times 3^x-3^x=6
The solution is x=0