What is the answer to (81^{x+5})/(3^{7x+2)}=3^{x-2} ?

The answer to (81^{x+5})/(3^{7x+2)}=3^{x-2} is x=5

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(81^{x+5})/(3^{7x+2)}=3^{x-2}

\frac{8 1 ^{x + 5}}{3 ^{7 x + 2}} = 3^{x - 2}

x = 5

Solution steps

\frac{8 1 ^{x + 5}}{3 ^{7 x + 2}} = 3^{x - 2}

Apply exponent rules

4 (x + 5) - 7 x - 2 = x - 2

Solve

4 (x + 5) - 7 x - 2 = x - 2 : x = 5

x = 5

Verify Solutions:

x = 5

True

The solution is

x = 5

4 \times 5^{x + 1} - 5 = 35

- e^{x} x = 0

n, (z^{2})^{n} = z^{10}

8^{x + 1} = 322

What is the answer to (81^{x+5})/(3^{7x+2)}=3^{x-2} ?
The answer to (81^{x+5})/(3^{7x+2)}=3^{x-2} is x=5
Solve for x: (81^{x+5})/(3^{7x+2)}=3^{x-2}
The solution is x=5