What is the answer to 7^x=9^{(x-1)} ?

The answer to 7^x=9^{(x-1)} is x=(2ln(3))/(2ln(3)-ln(7))

Solve for x: 7^x=9^{(x-1)}

The solution is x=(2ln(3))/(2ln(3)-ln(7))

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7^{x} = 9^{(x - 1)}

x = \frac{2 ln ( 3 )}{2 ln ( 3 ) - ln ( 7 )}

Decimal Notation

x = 8.74293 \dots

Solution steps

7^{x} = 9^{(x - 1)}

Apply exponent rules

x ln (7) = (x - 1) ln (9)

Solve

x ln (7) = (x - 1) ln (9) : x = \frac{2 ln ( 3 )}{2 ln ( 3 ) - ln ( 7 )}

x = \frac{2 ln ( 3 )}{2 ln ( 3 ) - ln ( 7 )}

4 9^{x} = 7

\frac{e ^{x}}{( 1 - e ^{x} ) ^{2}} = 0

- 6 \cdot e^{x - 2} - 5 = - 144

43 = 61 - 61 e^{- 0.24 x}

2^{2 x - 2} = 2^{x} + 48

What is the answer to 7^x=9^{(x-1)} ?
The answer to 7^x=9^{(x-1)} is x=(2ln(3))/(2ln(3)-ln(7))
Solve for x: 7^x=9^{(x-1)}
The solution is x=(2ln(3))/(2ln(3)-ln(7))