What is the answer to 2^{x+3}-2^{x+1}=12 ?

The answer to 2^{x+3}-2^{x+1}=12 is x=1

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2^{x+3}-2^{x+1}=12

2^{x + 3} - 2^{x + 1} = 12

x = 1

Solution steps

2^{x + 3} - 2^{x + 1} = 12

Factor

2^{x + 3} - 2^{x + 1} : 3 \cdot 2^{x + 1}

3 \cdot 2^{x + 1} = 12

Divide both sides by

3

2^{x + 1} = 4

Apply exponent rules

x + 1 = 2

Solve

x + 1 = 2 : x = 1

x = 1

2 e^{4 x - 6} = 16

5^{12 - x} = \frac{1}{125}

2^{2 x} = 2^{6} + 8^{2}

e^{x + 1} = 5^{x + 5}

5^{4 x + 3} = 30

What is the answer to 2^{x+3}-2^{x+1}=12 ?
The answer to 2^{x+3}-2^{x+1}=12 is x=1
Solve for x: 2^{x+3}-2^{x+1}=12
The solution is x=1