What is the answer to 2^x+3=2^{x+1} ?

The answer to 2^x+3=2^{x+1} is x=(ln(3))/(ln(2))

Solve for x: 2^x+3=2^{x+1}

The solution is x=(ln(3))/(ln(2))

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2^{x} + 3 = 2^{x + 1}

x = \frac{ln ( 3 )}{ln ( 2 )}

Decimal Notation

x = 1.58496 \dots

Solution steps

2^{x} + 3 = 2^{x + 1}

Subtract

2^{x + 1}

from both sides

2^{x} + 3 - 2^{x + 1} = 2^{x + 1} - 2^{x + 1}

Simplify

2^{x} + 3 - 2^{x + 1} = 0

Factor

2^{x} + 3 - 2^{x + 1} : - 2^{x} + 3

- 2^{x} + 3 = 0

Add

2^{x}

to both sides

- 2^{x} + 3 + 2^{x} = 0 + 2^{x}

Simplify

3 = 2^{x}

Apply exponent rules

ln (3) = x ln (2)

Solve

ln (3) = x ln (2) : x = \frac{ln ( 3 )}{ln ( 2 )}

x = \frac{ln ( 3 )}{ln ( 2 )}

8 = 60 t - 1800 + \frac{1800}{e ^{\frac{t}{30}}}

2^{x - 4} = 8

6^{x} - 9 \times 6^{- x} + 8 = 0

e^{2 x} = 12

e^{1 - 4 x} = 8

What is the answer to 2^x+3=2^{x+1} ?
The answer to 2^x+3=2^{x+1} is x=(ln(3))/(ln(2))
Solve for x: 2^x+3=2^{x+1}
The solution is x=(ln(3))/(ln(2))