What is the answer to 7^{-3-x}=242 ?

The answer to 7^{-3-x}=242 is x=-(ln(242)+3ln(7))/(ln(7))

Solve for x: 7^{-3-x}=242

The solution is x=-(ln(242)+3ln(7))/(ln(7))

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7^{- 3 - x} = 242

x = - \frac{ln ( 242 ) + 3 ln ( 7 )}{ln ( 7 )}

Decimal Notation

x = - 5.82075 \dots

Solution steps

7^{- 3 - x} = 242

Apply exponent rules

(- 3 - x) ln (7) = ln (242)

Solve

(- 3 - x) ln (7) = ln (242) : x = - \frac{ln ( 242 ) + 3 ln ( 7 )}{ln ( 7 )}

x = - \frac{ln ( 242 ) + 3 ln ( 7 )}{ln ( 7 )}

5^{2 x + 1} - 3 \times 5^{2 x - 1} = 550

62 5^{3 x} = 12 5^{x + 1}

3 x e^{x} - 8 e^{x} = 0

e^{2 x} + 2 e^{x} = + 24

3^{x^{2} + 6 x} = 9^{- 4}

What is the answer to 7^{-3-x}=242 ?
The answer to 7^{-3-x}=242 is x=-(ln(242)+3ln(7))/(ln(7))
Solve for x: 7^{-3-x}=242
The solution is x=-(ln(242)+3ln(7))/(ln(7))