What is the answer to 27^{x-3}=81^{2x-4} ?

The answer to 27^{x-3}=81^{2x-4} is x= 7/5

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27^{x-3}=81^{2x-4}

2 7^{x - 3} = 8 1^{2 x - 4}

x = \frac{7}{5}

Decimal Notation

x = 1.4

Solution steps

2 7^{x - 3} = 8 1^{2 x - 4}

Apply exponent rules

3 (x - 3) = 4 (2 x - 4)

Solve

3 (x - 3) = 4 (2 x - 4) : x = \frac{7}{5}

x = \frac{7}{5}

6 e^{4 x - 4} = 42

2 (e^{- x^{2}} - 2 e^{- x^{2}} x^{2}) = 0

2^{3 - x} = 4^{x}

e^{2 x} + 2 e^{x} - 3 = 0

e^{- x} (1 - x) = 0

What is the answer to 27^{x-3}=81^{2x-4} ?
The answer to 27^{x-3}=81^{2x-4} is x= 7/5
Solve for x: 27^{x-3}=81^{2x-4}
The solution is x= 7/5