What is the answer to 9*20^x=100 ?

The answer to 9*20^x=100 is x=(ln(100/9))/(ln(20))

Solve for x: 9*20^x=100

The solution is x=(ln(100/9))/(ln(20))

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9 \cdot 2 0^{x} = 100

x = \frac{ln ( \frac{100}{9} )}{ln ( 20 )}

Decimal Notation

x = 0.80379 \dots

Solution steps

9 \cdot 2 0^{x} = 100

Divide both sides by

9

2 0^{x} = \frac{100}{9}

Apply exponent rules

x ln (20) = ln (\frac{100}{9})

Solve

x ln (20) = ln (\frac{100}{9}) : x = \frac{ln ( \frac{100}{9} )}{ln ( 20 )}

x = \frac{ln ( \frac{100}{9} )}{ln ( 20 )}

3^{2 x + 2} - 28 \times 3^{x} + 3 = 0

2^{3 x - 2} = 3^{x + 1}

3^{x} + 3^{x + 4} + 3^{x - 1} = \frac{247}{27}

3^{5 x} = 2 7^{2 x - 4}

2^{x + 3} = 16

What is the answer to 9*20^x=100 ?
The answer to 9*20^x=100 is x=(ln(100/9))/(ln(20))
Solve for x: 9*20^x=100
The solution is x=(ln(100/9))/(ln(20))