What is the answer to solvefor x,5^{2x-3}=3^{3x+4} ?

The answer to solvefor x,5^{2x-3}=3^{3x+4} is x=(4ln(3)+3ln(5))/(2ln(5)-3ln(3))

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solvefor x,5^{2x-3}=3^{3x+4}

solve for

x, 5^{2 x - 3} = 3^{3 x + 4}

x = \frac{4 ln ( 3 ) + 3 ln ( 5 )}{2 ln ( 5 ) - 3 ln ( 3 )}

Decimal Notation

x = - 119.83677 \dots

Solution steps

5^{2 x - 3} = 3^{3 x + 4}

Apply exponent rules

(2 x - 3) ln (5) = (3 x + 4) ln (3)

Solve

(2 x - 3) ln (5) = (3 x + 4) ln (3) : x = \frac{4 ln ( 3 ) + 3 ln ( 5 )}{2 ln ( 5 ) - 3 ln ( 3 )}

x = \frac{4 ln ( 3 ) + 3 ln ( 5 )}{2 ln ( 5 ) - 3 ln ( 3 )}

12 5^{2 x + 3} = 5^{x + 4}

ln (e^{x} - 1) = 1

9^{x - 4} = 3^{x + 3}

0.12 5^{3 - x} = 128

4^{x^{2} + 3 x} = \frac{1}{16}

What is the answer to solvefor x,5^{2x-3}=3^{3x+4} ?
The answer to solvefor x,5^{2x-3}=3^{3x+4} is x=(4ln(3)+3ln(5))/(2ln(5)-3ln(3))