What is the answer to 8^{2x-5}=9^{1-2x} ?

The answer to 8^{2x-5}=9^{1-2x} is x=(2ln(3)+15ln(2))/(2ln(72))

Solve for x: 8^{2x-5}=9^{1-2x}

The solution is x=(2ln(3)+15ln(2))/(2ln(72))

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8^{2 x - 5} = 9^{1 - 2 x}

x = \frac{2 ln ( 3 ) + 15 ln ( 2 )}{2 ln ( 72 )}

Decimal Notation

x = 1.47245 \dots

Solution steps

8^{2 x - 5} = 9^{1 - 2 x}

Apply exponent rules

(2 x - 5) ln (8) = (1 - 2 x) ln (9)

Solve

(2 x - 5) ln (8) = (1 - 2 x) ln (9) : x = \frac{2 ln ( 3 ) + 15 ln ( 2 )}{2 ln ( 72 )}

x = \frac{2 ln ( 3 ) + 15 ln ( 2 )}{2 ln ( 72 )}

3^{\frac{x}{14}} = 0.1

0.55 = 1.01 5^{- x}

1 6^{r - 2} = 6 4^{r + 2}

4 e^{2 x} - 16 = 0

e^{2 x} + 2 e^{x} - 24 = 0

What is the answer to 8^{2x-5}=9^{1-2x} ?
The answer to 8^{2x-5}=9^{1-2x} is x=(2ln(3)+15ln(2))/(2ln(72))
Solve for x: 8^{2x-5}=9^{1-2x}
The solution is x=(2ln(3)+15ln(2))/(2ln(72))