What is the answer to 4^x=27 ?

The answer to 4^x=27 is x=(3ln(3))/(2ln(2))

The solution is x=(3ln(3))/(2ln(2))

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4^x=27

4^{x} = 27

x = \frac{3 ln ( 3 )}{2 ln ( 2 )}

Decimal

x = 2.37744 \dots

Solution steps

4^{x} = 27

Apply exponent rules

x ln (4) = ln (27)

Solve

x ln (4) = ln (27) : x = \frac{3 ln ( 3 )}{2 ln ( 2 )}

x = \frac{3 ln ( 3 )}{2 ln ( 2 )}

n, (x^{3})^{3} = x^{n}

4^{x} \times 3^{2 x} = 6

5 x = 4^{x + 1}

3^{4 - 2 x} = 9^{2 x}

5^{x} = 55