What is the answer to 3^x+20=28 ?

The answer to 3^x+20=28 is x=(3ln(2))/(ln(3))

Solve for x: 3^x+20=28

The solution is x=(3ln(2))/(ln(3))

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3^{x} + 20 = 28

x = \frac{3 ln ( 2 )}{ln ( 3 )}

Decimal

x = 1.89278 \dots

Solution steps

3^{x} + 20 = 28

Move

20

to the right side

3^{x} = 8

Apply exponent rules

x ln (3) = ln (8)

Solve

x ln (3) = ln (8) : x = \frac{3 ln ( 2 )}{ln ( 3 )}

x = \frac{3 ln ( 2 )}{ln ( 3 )}

y, e^{x + 2 y} = 0

2^{x} + 2^{2 x} = 2^{3 x}

41 - e^{2 x} = 5

e^{x} (x^{2} - 3 x + 1) = 0

2^{x + 2} + 2^{x - 1} = 6^{x - 1}