What is the answer to 10^{-x}=169 ?

The answer to 10^{-x}=169 is x=-(2ln(13))/(ln(10))

Solve for x: 10^{-x}=169

The solution is x=-(2ln(13))/(ln(10))

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1 0^{- x} = 169

x = - \frac{2 ln ( 13 )}{ln ( 10 )}

Decimal

x = - 2.22788 \dots

Solution steps

1 0^{- x} = 169

Apply exponent rules

- x ln (10) = ln (169)

Solve

- x ln (10) = ln (169) : x = - \frac{2 ln ( 13 )}{ln ( 10 )}

x = - \frac{2 ln ( 13 )}{ln ( 10 )}

- e^{x} x - 6 e^{x} = 0

3^{x + 1} = 4^{x}

3 6^{x - 5} = \frac{1}{6}

25 = \frac{100 ( 0.5 ) ^{t}}{5730}

2 (7^{x}) = 686

What is the answer to 10^{-x}=169 ?
The answer to 10^{-x}=169 is x=-(2ln(13))/(ln(10))
Solve for x: 10^{-x}=169
The solution is x=-(2ln(13))/(ln(10))