What is the answer to \sqrt[3]{4^{x+1}}=1 ?

The answer to \sqrt[3]{4^{x+1}}=1 is x=-1

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\sqrt[3]{4^{x+1}}=1

3 4^{x + 1} = 1

x = - 1

Solution steps

3 4^{x + 1} = 1

Apply exponent rules

(x + 1) \frac{1}{3} ln (4) = ln (1)

Solve

(x + 1) \frac{1}{3} ln (4) = ln (1) : x = - 1

x = - 1

2^{2 x} = 6

3^{\frac{x}{5}} = 2^{4 x - 2}

2^{x + 1} - 2^{x} = 8

3 e^{x} + 7 = 9

5^{x} + 5^{x + 2} = 650

What is the answer to \sqrt[3]{4^{x+1}}=1 ?
The answer to \sqrt[3]{4^{x+1}}=1 is x=-1
Solve for x: \sqrt[3]{4^{x+1}}=1
The solution is x=-1