What is the answer to sqrt(3)^{3x-1}=6^{x-5} ?

The answer to sqrt(3)^{3x-1}=6^{x-5} is x=(ln(20155392))/(ln(4/3))

Solve for x: sqrt(3)^{3x-1}=6^{x-5}

The solution is x=(ln(20155392))/(ln(4/3))

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3^{3 x - 1} = 6^{x - 5}

x = \frac{ln ( 20155392 )}{ln ( \frac{4}{3} )}

Decimal

x = 58.46378 \dots

Solution steps

(3)^{3 x - 1} = 6^{x - 5}

Apply exponent rules

\frac{1}{2} (3 x - 1) ln (3) = (x - 5) ln (6)

Solve

\frac{1}{2} (3 x - 1) ln (3) = (x - 5) ln (6) : x = \frac{ln ( 20155392 )}{ln ( \frac{4}{3} )}

x = \frac{ln ( 20155392 )}{ln ( \frac{4}{3} )}

e^{x} - e = 0

2^{2 x + 1} - 5 \cdot 2^{x} + 2 = 0

U (t) e^{t} - V (t) e^{- t} = 0

2 = 2^{x} + x - 1

3 e^{3 x + 4} - 8 = e

What is the answer to sqrt(3)^{3x-1}=6^{x-5} ?
The answer to sqrt(3)^{3x-1}=6^{x-5} is x=(ln(20155392))/(ln(4/3))
Solve for x: sqrt(3)^{3x-1}=6^{x-5}
The solution is x=(ln(20155392))/(ln(4/3))