What is the answer to 4^{2x}=625^{3x+5} ?

The answer to 4^{2x}=625^{3x+5} is x=(5ln(5))/(ln(2)-3ln(5))

Solve for x: 4^{2x}=625^{3x+5}

The solution is x=(5ln(5))/(ln(2)-3ln(5))

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4^{2 x} = 62 5^{3 x + 5}

x = \frac{5 ln ( 5 )}{ln ( 2 ) - 3 ln ( 5 )}

Decimal Notation

x = - 1.94603 \dots

Solution steps

4^{2 x} = 62 5^{3 x + 5}

Apply exponent rules

2 x ln (4) = (3 x + 5) ln (625)

Solve

2 x ln (4) = (3 x + 5) ln (625) : x = \frac{5 ln ( 5 )}{ln ( 2 ) - 3 ln ( 5 )}

x = \frac{5 ln ( 5 )}{ln ( 2 ) - 3 ln ( 5 )}

\frac{1}{2} = 1 - e^{- 2 x}

7^{x - 1} = 49

7 \cdot 9^{x} - 2 \cdot 3^{2 x + 1} = 90 - 3^{x}

7^{9 x - 2} = 1 0^{2 x - 2}

4^{3 x} = 8

What is the answer to 4^{2x}=625^{3x+5} ?
The answer to 4^{2x}=625^{3x+5} is x=(5ln(5))/(ln(2)-3ln(5))
Solve for x: 4^{2x}=625^{3x+5}
The solution is x=(5ln(5))/(ln(2)-3ln(5))