What is the answer to 56*2^{2x}=22 ?

The answer to 56*2^{2x}=22 is x=(ln(11/28))/(2ln(2))

Solve for x: 56*2^{2x}=22

The solution is x=(ln(11/28))/(2ln(2))

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56 \cdot 2^{2 x} = 22

x = \frac{ln ( \frac{11}{28} )}{2 ln ( 2 )}

Decimal Notation

x = - 0.67396 \dots

Solution steps

56 \cdot 2^{2 x} = 22

Divide both sides by

56

2^{2 x} = \frac{11}{28}

Apply exponent rules

2 x ln (2) = ln (\frac{11}{28})

Solve

2 x ln (2) = ln (\frac{11}{28}) : x = \frac{ln ( \frac{11}{28} )}{2 ln ( 2 )}

x = \frac{ln ( \frac{11}{28} )}{2 ln ( 2 )}

27 \times 3^{x} = 1

k, n = 2^{k}

e^{3 x} - 3 e^{- 3 x} = 0

y, x = 2 - 2^{y}

2 7^{3 n} = 8 1^{2 n + 1}

What is the answer to 56*2^{2x}=22 ?
The answer to 56*2^{2x}=22 is x=(ln(11/28))/(2ln(2))
Solve for x: 56*2^{2x}=22
The solution is x=(ln(11/28))/(2ln(2))