What is the answer to 2^{4x}+2^{2x+3}+2^4=0 ?

The answer to 2^{4x}+2^{2x+3}+2^4=0 is No Solution for x\in\mathbb{R}

Solve for x: 2^{4x}+2^{2x+3}+2^4=0

The solution is No Solution for x\in\mathbb{R}

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2^{4 x} + 2^{2 x + 3} + 2^{4} = 0

No Solution for x \in R

Solution steps

2^{4 x} + 2^{2 x + 3} + 2^{4} = 0

Apply exponent rules

(2^{x})^{4} + (2^{x})^{2} \cdot 2^{3} + 2^{4} = 0

Rewrite the equation with

2^{x} = u

(u)^{4} + (u)^{2} \cdot 2^{3} + 2^{4} = 0

Solve

u^{4} + u^{2} \cdot 2^{3} + 2^{4} = 0 :

No Solution for

u \in R

No Solution for x \in R

4^{2 x} = 16

t, f = A e^{Bt}

0.00 1^{x} = 0.1

5 (4^{x}) = 10

1 4^{x} = 8

What is the answer to 2^{4x}+2^{2x+3}+2^4=0 ?
The answer to 2^{4x}+2^{2x+3}+2^4=0 is No Solution for x\in\mathbb{R}
Solve for x: 2^{4x}+2^{2x+3}+2^4=0
The solution is No Solution for x\in\mathbb{R}