What is the answer to 4^{2x+7}=32^{2x-3} ?

The answer to 4^{2x+7}=32^{2x-3} is x= 29/6

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4^{2x+7}=32^{2x-3}

4^{2 x + 7} = 3 2^{2 x - 3}

x = \frac{29}{6}

Decimal Notation

x = 4.83333 \dots

Solution steps

4^{2 x + 7} = 3 2^{2 x - 3}

Apply exponent rules

2 (2 x + 7) = 5 (2 x - 3)

Solve

2 (2 x + 7) = 5 (2 x - 3) : x = \frac{29}{6}

x = \frac{29}{6}

(5^{x})^{- 1} = 25

32 = 2^{x - 3}

\frac{1}{16} = 2^{x}

1 0^{5 x} = 8

e^{2 x} - 5 e^{x} = 24

What is the answer to 4^{2x+7}=32^{2x-3} ?
The answer to 4^{2x+7}=32^{2x-3} is x= 29/6
Solve for x: 4^{2x+7}=32^{2x-3}
The solution is x= 29/6