What is the answer to 5^{x+1}+5^x+5^{x-1}=31 ?

The answer to 5^{x+1}+5^x+5^{x-1}=31 is x=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5^{x+1}+5^x+5^{x-1}=31

5^{x + 1} + 5^{x} + 5^{x - 1} = 31

x = 1

Solution steps

5^{x + 1} + 5^{x} + 5^{x - 1} = 31

Factor

5^{x + 1} + 5^{x} + 5^{x - 1} : 31 \cdot 5^{x - 1}

31 \cdot 5^{x - 1} = 31

Divide both sides by

31

5^{x - 1} = 1

Apply exponent rules

(x - 1) ln (5) = ln (1)

Solve

(x - 1) ln (5) = ln (1) : x = 1

x = 1

2^{x + 2} + 5 \times 2^{x - 1} = \frac{13}{16}

4 e^{3 - x} = 3^{2 x + 5}

5^{n} = 125

- e^{- x} - 1 = 0

e^{- 2 x} = \frac{1}{2}

What is the answer to 5^{x+1}+5^x+5^{x-1}=31 ?
The answer to 5^{x+1}+5^x+5^{x-1}=31 is x=1
Solve for x: 5^{x+1}+5^x+5^{x-1}=31
The solution is x=1