What are the solutions to the equation 2x^2-9x+7=0 ?

The solutions to the equation 2x^2-9x+7=0 are x= 7/2 ,x=1

Find the zeros of 2x^2-9x+7=0

The zeros of 2x^2-9x+7=0 are x= 7/2 ,x=1

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2 x^{2} - 9 x + 7 = 0

x = \frac{7}{2}, x = 1

Decimal Notation

x = 3.5, x = 1

Solution steps

2 x^{2} - 9 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 2 \cdot 7}{2 \cdot 2}

(- 9)^{2} - 4 \cdot 2 \cdot 7 = 5

x_{1, 2} = \frac{- ( - 9 ) \pm 5}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 5}{2 \cdot 2}, x_{2} = \frac{- ( - 9 ) - 5}{2 \cdot 2}

x = \frac{- ( - 9 ) + 5}{2 \cdot 2} : \frac{7}{2}

x = \frac{- ( - 9 ) - 5}{2 \cdot 2} : 1

The solutions to the quadratic equation are:

x = \frac{7}{2}, x = 1

\frac{1}{2} \cdot \frac{4}{9}

4 ab + 2 a + 6 b + 3

x (x + 3) (x - 3) \leq 0

∣ x + 6 ∣ \leq 10

lo g_{343} (7)

What are the solutions to the equation 2x^2-9x+7=0 ?
The solutions to the equation 2x^2-9x+7=0 are x= 7/2 ,x=1
Find the zeros of 2x^2-9x+7=0
The zeros of 2x^2-9x+7=0 are x= 7/2 ,x=1