What is the answer to 5^{3x-1}=2 ?

The answer to 5^{3x-1}=2 is x=(ln(10))/(3ln(5))

Solve for x: 5^{3x-1}=2

The solution is x=(ln(10))/(3ln(5))

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5^{3 x - 1} = 2

x = \frac{ln ( 10 )}{3 ln ( 5 )}

Decimal Notation

x = 0.47689 \dots

Solution steps

5^{3 x - 1} = 2

Apply exponent rules

(3 x - 1) ln (5) = ln (2)

Solve

(3 x - 1) ln (5) = ln (2) : x = \frac{ln ( 10 )}{3 ln ( 5 )}

x = \frac{ln ( 10 )}{3 ln ( 5 )}

e^{3 x - 4} \cdot e^{- x} = 4 e

1 - 3 e^{- 3 x} = 0

y, e^{5 x - y} = 3 e^{3 x}

4^{x} - 3 \times 2^{x} + 2 = 0

(0.5)^{2 x} = 2^{1 - 3 x}

What is the answer to 5^{3x-1}=2 ?
The answer to 5^{3x-1}=2 is x=(ln(10))/(3ln(5))
Solve for x: 5^{3x-1}=2
The solution is x=(ln(10))/(3ln(5))