What is the answer to 4^x+5\times 2^{2x}=24\sqrt[6]{2} ?

The answer to 4^x+5\times 2^{2x}=24\sqrt[6]{2} is x= 13/12

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4^x+5\times 2^{2x}=24\sqrt[6]{2}

x = \frac{13}{12}

Decimal Notation

x = 1.08333 \dots

Solution steps

Move

5 \cdot 2^{2 x}

to the right side

Move

5 \cdot 4^{x}

to the left side

Divide both sides by

6

Apply exponent rules

2 x = \frac{13}{6}

Solve

2 x = \frac{13}{6} : x = \frac{13}{12}

x = \frac{13}{12}

e^{2 x} - 2 e^{x} = 8

1 6^{x - 3} = 3^{- 5 x}

10 e^{8 x - 3} + 2 = 8 e^{8 x}

4^{3 x} = 8^{x} + 3

3^{3 x - 10} = \frac{1}{27} 3

What is the answer to 4^x+5\times 2^{2x}=24\sqrt[6]{2} ?
The answer to 4^x+5\times 2^{2x}=24\sqrt[6]{2} is x= 13/12
Solve for x: 4^x+5\times 2^{2x}=24\sqrt[6]{2}
The solution is x= 13/12