What is the answer to 16^{x^2+1}=2^{4x+7} ?

The answer to 16^{x^2+1}=2^{4x+7} is x= 3/2 ,x=-1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

16^{x^2+1}=2^{4x+7}

1 6^{x^{2} + 1} = 2^{4 x + 7}

x = \frac{3}{2}, x = - \frac{1}{2}

Decimal Notation

x = 1.5, x = - 0.5

Solution steps

1 6^{x^{2} + 1} = 2^{4 x + 7}

Apply exponent rules

4 (x^{2} + 1) = 4 x + 7

Solve

4 (x^{2} + 1) = 4 x + 7 : x = \frac{3}{2}, x = - \frac{1}{2}

x = \frac{3}{2}, x = - \frac{1}{2}

5^{2 x - 1} - 5^{2 x - 3} = 4.8

7 e^{7 x} - e^{- x} = 0

x e^{- x} - 2 e^{- x} = 0

1 = e^{2 x}

1 3^{x} = 4

What is the answer to 16^{x^2+1}=2^{4x+7} ?
The answer to 16^{x^2+1}=2^{4x+7} is x= 3/2 ,x=-1/2
Solve for x: 16^{x^2+1}=2^{4x+7}
The solution is x= 3/2 ,x=-1/2