What are the solutions to the equation 99=-16(t)(t)+80(t)+3 ?

The solutions to the equation 99=-16(t)(t)+80(t)+3 are t=2,t=3

Find the zeros of 99=-16(t)(t)+80(t)+3

The zeros of 99=-16(t)(t)+80(t)+3 are t=2,t=3

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99 = - 16 (t) (t) + 80 (t) + 3

t = 2, t = 3

Solution steps

99 = - 16 (t) (t) + 80 (t) + 3

Expand

- 16 (t) (t) + 80 (t) + 3 : - 16 t^{2} + 80 t + 3

99 = - 16 t^{2} + 80 t + 3

Switch sides

- 16 t^{2} + 80 t + 3 = 99

Move

99

to the left side

- 16 t^{2} + 80 t - 96 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 80 \pm 8 0 ^{2} - 4 ( - 16 ) ( - 96 )}{2 ( - 16 )}

8 0^{2} - 4 (- 16) (- 96) = 16

t_{1, 2} = \frac{- 80 \pm 16}{2 ( - 16 )}

Separate the solutions

t_{1} = \frac{- 80 + 16}{2 ( - 16 )}, t_{2} = \frac{- 80 - 16}{2 ( - 16 )}

t = \frac{- 80 + 16}{2 ( - 16 )} : 2

t = \frac{- 80 - 16}{2 ( - 16 )} : 3

The solutions to the quadratic equation are:

t = 2, t = 3

2 x^{2} - 4 x - 5 = 0

10 a^{4} - a^{3} - 21 a^{2}

(x - 2)^{3} - x (x - 5) \cdot (x - 1) = 2 - 3 x

(1 + i)^{8}

n^{3} + 5 n^{2} - 9 n - 45

What are the solutions to the equation 99=-16(t)(t)+80(t)+3 ?
The solutions to the equation 99=-16(t)(t)+80(t)+3 are t=2,t=3
Find the zeros of 99=-16(t)(t)+80(t)+3
The zeros of 99=-16(t)(t)+80(t)+3 are t=2,t=3