What is the answer to 4^{2x}=9^{x-1} ?

The answer to 4^{2x}=9^{x-1} is x=-(ln(3))/(2ln(2)-ln(3))

Solve for x: 4^{2x}=9^{x-1}

The solution is x=-(ln(3))/(2ln(2)-ln(3))

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4^{2 x} = 9^{x - 1}

x = - \frac{ln ( 3 )}{2 ln ( 2 ) - ln ( 3 )}

Decimal Notation

x = - 3.81884 \dots

Solution steps

4^{2 x} = 9^{x - 1}

Apply exponent rules

2 x ln (4) = (x - 1) ln (9)

Solve

2 x ln (4) = (x - 1) ln (9) : x = - \frac{ln ( 3 )}{2 ln ( 2 ) - ln ( 3 )}

x = - \frac{ln ( 3 )}{2 ln ( 2 ) - ln ( 3 )}

3 \cdot 5^{x + 1} - 1 = 11

x, 2^{2 x} - 4^{x - 1} = 12

3^{2 x} - 3^{x + 2} + 8 = 0

e^{- 2 t} - 4 \cdot e^{- t} + 4 = 0

4^{- 3 v} = 64

What is the answer to 4^{2x}=9^{x-1} ?
The answer to 4^{2x}=9^{x-1} is x=-(ln(3))/(2ln(2)-ln(3))
Solve for x: 4^{2x}=9^{x-1}
The solution is x=-(ln(3))/(2ln(2)-ln(3))