What is the answer to (1/3)^x=9^{1-2x} ?

The answer to (1/3)^x=9^{1-2x} is x= 2/3

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(1/3)^x=9^{1-2x}

(\frac{1}{3})^{x} = 9^{1 - 2 x}

x = \frac{2}{3}

Decimal

x = 0.66666 \dots

Solution steps

(\frac{1}{3})^{x} = 9^{1 - 2 x}

Apply exponent rules

- x = 2 (1 - 2 x)

Solve

- x = 2 (1 - 2 x) : x = \frac{2}{3}

x = \frac{2}{3}

(5^{x})^{3} 5^{2 x - 1} = 5

m, 1 = y^{6 m}

90 = 30 e^{0.03 \cdot x}

e^{2 x} - e^{x} - 56 = 0

4 9^{x + 3} = 7^{x + 2}

What is the answer to (1/3)^x=9^{1-2x} ?
The answer to (1/3)^x=9^{1-2x} is x= 2/3
Solve for x: (1/3)^x=9^{1-2x}
The solution is x= 2/3