What is the answer to 16^{x+2}=32^{2x-1} ?

The answer to 16^{x+2}=32^{2x-1} is x= 13/6

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16^{x+2}=32^{2x-1}

1 6^{x + 2} = 3 2^{2 x - 1}

x = \frac{13}{6}

Decimal Notation

x = 2.16666 \dots

Solution steps

1 6^{x + 2} = 3 2^{2 x - 1}

Apply exponent rules

4 (x + 2) = 5 (2 x - 1)

Solve

4 (x + 2) = 5 (2 x - 1) : x = \frac{13}{6}

x = \frac{13}{6}

e^{3 x} + 3 e^{3 x} x = 0

2 5^{x} - 23 \times 5^{x} = 50

5^{x} + 5^{x - 1} + 5^{x - 3} + 5^{x - 4} = 455

2 5^{x - 3} = 5125

x e^{x} + 1 = 0

What is the answer to 16^{x+2}=32^{2x-1} ?
The answer to 16^{x+2}=32^{2x-1} is x= 13/6
Solve for x: 16^{x+2}=32^{2x-1}
The solution is x= 13/6