What is the answer to (5*2^{3x-1})/(4^{2x-1)}=80 ?

The answer to (5*2^{3x-1})/(4^{2x-1)}=80 is x=-3

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(5*2^{3x-1})/(4^{2x-1)}=80

\frac{5 \cdot 2 ^{3 x - 1}}{4 ^{2 x - 1}} = 80

x = - 3

Solution steps

\frac{5 \cdot 2 ^{3 x - 1}}{4 ^{2 x - 1}} = 80

Apply exponent rules

3 x - 1 + 2 (- 2 x + 1) = 4

Solve

3 x - 1 + 2 (- 2 x + 1) = 4 : x = - 3

x = - 3

Verify Solutions:

x = - 3

True

The solution is

x = - 3

35 e^{- 0.001 x} = 95

3^{3 x} + 3^{2 - x} = 10 \cdot 3^{x}

8^{2 x - 1} = 16

5^{3 x - 1} = 0.2

5^{3 x - 1} = 125

What is the answer to (5*2^{3x-1})/(4^{2x-1)}=80 ?
The answer to (5*2^{3x-1})/(4^{2x-1)}=80 is x=-3
Solve for x: (5*2^{3x-1})/(4^{2x-1)}=80
The solution is x=-3