What is the answer to 2^x=38 ?

The answer to 2^x=38 is x=(ln(38))/(ln(2))

The solution is x=(ln(38))/(ln(2))

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2^x=38

2^{x} = 38

x = \frac{ln ( 38 )}{ln ( 2 )}

Decimal

x = 5.24792 \dots

Solution steps

2^{x} = 38

Apply exponent rules

x ln (2) = ln (38)

Solve

x ln (2) = ln (38) : x = \frac{ln ( 38 )}{ln ( 2 )}

x = \frac{ln ( 38 )}{ln ( 2 )}

e^{6 x} = 7

9^{x} + 3^{x + 3} = 28

2^{n} = 128

2 7^{1 - x} = \frac{1}{81}

4^{2 x - 7} = 64