What is the answer to 3^{4x+1}=8^{x-5} ?

The answer to 3^{4x+1}=8^{x-5} is x=(-15ln(2)-ln(3))/(4ln(3)-3ln(2))

Solve for x: 3^{4x+1}=8^{x-5}

The solution is x=(-15ln(2)-ln(3))/(4ln(3)-3ln(2))

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3^{4 x + 1} = 8^{x - 5}

x = \frac{- 15 ln ( 2 ) - ln ( 3 )}{4 ln ( 3 ) - 3 ln ( 2 )}

Decimal Notation

x = - 4.96578 \dots

Solution steps

3^{4 x + 1} = 8^{x - 5}

Apply exponent rules

(4 x + 1) ln (3) = (x - 5) ln (8)

Solve

(4 x + 1) ln (3) = (x - 5) ln (8) : x = \frac{- 15 ln ( 2 ) - ln ( 3 )}{4 ln ( 3 ) - 3 ln ( 2 )}

x = \frac{- 15 ln ( 2 ) - ln ( 3 )}{4 ln ( 3 ) - 3 ln ( 2 )}

5^{2 x} + 5^{x} - 6 = 0

2 5^{x - 3} = 125

4^{x} - 2^{x + 2} = 12

9^{x} = 3

\frac{100 e ^{x}}{e ^{x} + 2} = 50

What is the answer to 3^{4x+1}=8^{x-5} ?
The answer to 3^{4x+1}=8^{x-5} is x=(-15ln(2)-ln(3))/(4ln(3)-3ln(2))
Solve for x: 3^{4x+1}=8^{x-5}
The solution is x=(-15ln(2)-ln(3))/(4ln(3)-3ln(2))