What is the answer to 3^{2x}-4(3^x)+3=0 ?

The answer to 3^{2x}-4(3^x)+3=0 is x=1,x=0

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3^{2x}-4(3^x)+3=0

3^{2 x} - 4 (3^{x}) + 3 = 0

x = 1, x = 0

Solution steps

3^{2 x} - 4 (3^{x}) + 3 = 0

Apply exponent rules

(3^{x})^{2} - 4 \cdot 3^{x} + 3 = 0

Rewrite the equation with

3^{x} = u

(u)^{2} - 4 u + 3 = 0

Solve

u^{2} - 4 u + 3 = 0 : u = 3, u = 1

u = 3, u = 1

Substitute back

u = 3^{x},

solve for

x

Solve

3^{x} = 3 : x = 1

Solve

3^{x} = 1 : x = 0

x = 1, x = 0

1 6^{- 3} = 8^{x - 3}

2^{3 x} = 4^{x + 4}

2 (5^{x + 1}) = 1 + \frac{3}{5 ^{x}}

3^{x} = 33

5 e^{3 x} - 4 = 6

What is the answer to 3^{2x}-4(3^x)+3=0 ?
The answer to 3^{2x}-4(3^x)+3=0 is x=1,x=0
Solve for x: 3^{2x}-4(3^x)+3=0
The solution is x=1,x=0