What is the answer to (49^{4x-1})/(7^{x-6)}=7^{8x+3} ?

The answer to (49^{4x-1})/(7^{x-6)}=7^{8x+3} is x=1

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(49^{4x-1})/(7^{x-6)}=7^{8x+3}

\frac{4 9 ^{4 x - 1}}{7 ^{x - 6}} = 7^{8 x + 3}

x = 1

Solution steps

\frac{4 9 ^{4 x - 1}}{7 ^{x - 6}} = 7^{8 x + 3}

Apply exponent rules

2 (4 x - 1) - x + 6 = 8 x + 3

Solve

2 (4 x - 1) - x + 6 = 8 x + 3 : x = 1

x = 1

Verify Solutions:

x = 1

True

The solution is

x = 1

3^{x^{2}} + 18 = 27

3^{2 x - 3} = 729

3 = 2 + 5 e^{- 4 x}

3^{l o g_{9} (5 x - 5)} = 5

(x + 5) e^{- 2 x} = 0

What is the answer to (49^{4x-1})/(7^{x-6)}=7^{8x+3} ?
The answer to (49^{4x-1})/(7^{x-6)}=7^{8x+3} is x=1
Solve for x: (49^{4x-1})/(7^{x-6)}=7^{8x+3}
The solution is x=1