What is the answer to 2^x=16000 ?

The answer to 2^x=16000 is x=(ln(16000))/(ln(2))

Solve for x: 2^x=16000

The solution is x=(ln(16000))/(ln(2))

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2^{x} = 16000

x = \frac{ln ( 16000 )}{ln ( 2 )}

Decimal Notation

x = 13.96578 \dots

Solution steps

2^{x} = 16000

Apply exponent rules

x ln (2) = ln (16000)

Solve

x ln (2) = ln (16000) : x = \frac{ln ( 16000 )}{ln ( 2 )}

x = \frac{ln ( 16000 )}{ln ( 2 )}

105 0^{x} + 105 0^{x + 1} + 105 0^{x + 2} = 2021

4^{x} = 26

4^{x} = 21

4 \times 7^{x} = 4

- 3^{x} = - 3^{13}

What is the answer to 2^x=16000 ?
The answer to 2^x=16000 is x=(ln(16000))/(ln(2))
Solve for x: 2^x=16000
The solution is x=(ln(16000))/(ln(2))