What is the answer to 4^x=21 ?

The answer to 4^x=21 is x=(ln(21))/(2ln(2))

The solution is x=(ln(21))/(2ln(2))

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4^x=21

4^{x} = 21

x = \frac{ln ( 21 )}{2 ln ( 2 )}

Decimal Notation

x = 2.19615 \dots

Solution steps

4^{x} = 21

Apply exponent rules

x ln (4) = ln (21)

Solve

x ln (4) = ln (21) : x = \frac{ln ( 21 )}{2 ln ( 2 )}

x = \frac{ln ( 21 )}{2 ln ( 2 )}

4 \times 7^{x} = 4

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