What is the answer to 3^{x+1}\times 2^{x+1}=36 ?

The answer to 3^{x+1}\times 2^{x+1}=36 is x=1

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3^{x+1}\times 2^{x+1}=36

3^{x + 1} \cdot 2^{x + 1} = 36

x = 1

Solution steps

3^{x + 1} \cdot 2^{x + 1} = 36

Apply exponent rules

x + 1 = 2

Solve

x + 1 = 2 : x = 1

x = 1

e^{x} x^{6} + 6 e^{x} x^{5} = 0

5^{x + 2} - 5^{x} = 120

e^{z^{2}} = - 1

(\frac{1}{8})^{5 x} = 3 2^{x + 8}

2^{2 x - 3} = 5^{2 - x}

What is the answer to 3^{x+1}\times 2^{x+1}=36 ?
The answer to 3^{x+1}\times 2^{x+1}=36 is x=1
Solve for x: 3^{x+1}\times 2^{x+1}=36
The solution is x=1