What is the answer to 9^x+3=4\times 3^x ?

The answer to 9^x+3=4\times 3^x is x=1,x=0

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9^x+3=4\times 3^x

9^{x} + 3 = 4 \cdot 3^{x}

x = 1, x = 0

Solution steps

9^{x} + 3 = 4 \cdot 3^{x}

Apply exponent rules

(3^{x})^{2} + 3 = 4 \cdot 3^{x}

Rewrite the equation with

3^{x} = u

(u)^{2} + 3 = 4 u

Solve

u^{2} + 3 = 4 u : u = 3, u = 1

u = 3, u = 1

Substitute back

u = 3^{x},

solve for

x

Solve

3^{x} = 3 : x = 1

Solve

3^{x} = 1 : x = 0

x = 1, x = 0

2^{x + 1} = 3^{2 - 2 x}

x, (x y)^{x} = e

0. 5^{x} = 0.15

5^{2 x - 1} = 0.2

1 0^{2 x + 1} = 115

What is the answer to 9^x+3=4\times 3^x ?
The answer to 9^x+3=4\times 3^x is x=1,x=0
Solve for x: 9^x+3=4\times 3^x
The solution is x=1,x=0