What is the answer to 7(3)^{x+1}-5^{x+2}=3^{x+4}-5^{x+3} ?

The answer to 7(3)^{x+1}-5^{x+2}=3^{x+4}-5^{x+3} is x=-1

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7(3)^{x+1}-5^{x+2}=3^{x+4}-5^{x+3}

7 (3)^{x + 1} - 5^{x + 2} = 3^{x + 4} - 5^{x + 3}

x = - 1

Solution steps

7 (3)^{x + 1} - 5^{x + 2} = 3^{x + 4} - 5^{x + 3}

Move

3^{x + 4}

to the left side

- 20 \cdot 3^{x + 1} - 5^{x + 2} = - 5^{x + 3}

Move

5^{x + 2}

to the right side

- 20 \cdot 3^{x + 1} = - 4 \cdot 5^{x + 2}

Divide both sides by

- 4

\frac{- 20 \cdot 3 ^{x + 1}}{- 4} = \frac{- 4 \cdot 5 ^{x + 2}}{- 4}

Simplify

5 \cdot 3^{x + 1} = 5^{x + 2}

Apply exponent rules

ln (5) + (x + 1) ln (3) = (x + 2) ln (5)

Solve

ln (5) + (x + 1) ln (3) = (x + 2) ln (5) : x = - 1

x = - 1

16 = 0.5 \times 2^{x - 1}

3^{3 x + 5} = 3 \times 9^{x + 3}

2^{1 - 6 x} = 7^{3 x + 4}

y, 9^{x + 3} - 2 7^{2 y} = - 3535662

e^{x} = 1 + x

What is the answer to 7(3)^{x+1}-5^{x+2}=3^{x+4}-5^{x+3} ?
The answer to 7(3)^{x+1}-5^{x+2}=3^{x+4}-5^{x+3} is x=-1
Solve for x: 7(3)^{x+1}-5^{x+2}=3^{x+4}-5^{x+3}
The solution is x=-1