What is factor n^2+4n+3 ?

The solution to factor n^2+4n+3 is (n+1)(n+3)

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factor n^2+4n+3

factor

n^{2} + 4 n + 3

(n + 1) (n + 3)

Solution steps

n^{2} + 4 n + 3

Break the expression into groups

= (n^{2} + n) + (3 n + 3)

Factor out

n

from

n^{2} + n : n (n + 1)

Factor out

3

from

3 n + 3 : 3 (n + 1)

= n (n + 1) + 3 (n + 1)

Factor out common term

n + 1

= (n + 1) (n + 3)

y, y^{2} = c x^{3} - 2 x

240 = v + \frac{v ^{2}}{20}

\frac{x - 1}{x + 7} \geq 0

0.0001

7 < - (- k - 3) + 2