What is the answer to \sqrt[7]{625^x}= 1/(125^{-x+3)} ?

The answer to \sqrt[7]{625^x}= 1/(125^{-x+3)} is x= 63/17

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\sqrt[7]{625^x}= 1/(125^{-x+3)}

x = \frac{63}{17}

Decimal Notation

x = 3.70588 \dots

Solution steps

Apply exponent rules

\frac{4}{7} x = 3 (x - 3)

Solve

\frac{4}{7} x = 3 (x - 3) : x = \frac{63}{17}

x = \frac{63}{17}

Verify Solutions:

x = \frac{63}{17}

True

The solution is

x = \frac{63}{17}

27 = 9^{x}

5^{2 x + 1} = 1

y, x^{y} = 2

e^{x} = 36

What is the answer to \sqrt[7]{625^x}= 1/(125^{-x+3)} ?
The answer to \sqrt[7]{625^x}= 1/(125^{-x+3)} is x= 63/17
Solve for x: \sqrt[7]{625^x}= 1/(125^{-x+3)}
The solution is x= 63/17