What is the answer to solvefor x,81^{4x+4}=3^{x^2+10x-11} ?

The answer to solvefor x,81^{4x+4}=3^{x^2+10x-11} is x=9,x=-3

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solvefor x,81^{4x+4}=3^{x^2+10x-11}

solve for

x, 8 1^{4 x + 4} = 3^{x^{2} + 10 x - 11}

x = 9, x = - 3

Solution steps

8 1^{4 x + 4} = 3^{x^{2} + 10 x - 11}

Apply exponent rules

4 (4 x + 4) = x^{2} + 10 x - 11

Solve

4 (4 x + 4) = x^{2} + 10 x - 11 : x = 9, x = - 3

x = 9, x = - 3

4 9^{x + 1} = (\frac{1}{7})^{x}

4 \cdot 5^{x} + 25 = 5^{x + 1} - 4 \cdot 5^{x - 1}

e^{x + 1} - 2^{3 - x} = 0

9^{2 x - 4} = 2 7^{x - 1}

91500 = 100000 - 272000 (\frac{1}{2})^{x}

What is the answer to solvefor x,81^{4x+4}=3^{x^2+10x-11} ?
The answer to solvefor x,81^{4x+4}=3^{x^2+10x-11} is x=9,x=-3