What is the answer to log_{2}(4^{x+4})=-2 ?

The answer to log_{2}(4^{x+4})=-2 is x=-5

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log_{2}(4^{x+4})=-2

lo g_{2} (4^{x + 4}) = - 2

x = - 5

Solution steps

lo g_{2} (4^{x + 4}) = - 2

Rewrite the equation with

4^{x + 4} = u

lo g_{2} (u) = - 2

Solve

lo g_{2} (u) = - 2 : u = \frac{1}{4}

u = \frac{1}{4}

Substitute back

u = 4^{x + 4},

solve for

x

Solve

4^{x + 4} = \frac{1}{4} : x = - 5

x = - 5

x^{l o g_{10} (x)} = 10

2 e^{2 x} + e^{x} = 6

e^{x + 3} = 5

1 6^{- x} = 4

m, 2^{m + 1} + 2^{m} = 3^{n + 2} - 3^{n}

What is the answer to log_{2}(4^{x+4})=-2 ?
The answer to log_{2}(4^{x+4})=-2 is x=-5
Solve for x: log_{2}(4^{x+4})=-2
The solution is x=-5