What is the answer to 62*10^x=40 ?

The answer to 62*10^x=40 is x=(ln(20/31))/(ln(10))

Solve for x: 62*10^x=40

The solution is x=(ln(20/31))/(ln(10))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

62 \cdot 1 0^{x} = 40

x = \frac{ln ( \frac{20}{31} )}{ln ( 10 )}

Decimal Notation

x = - 0.19033 \dots

Solution steps

62 \cdot 1 0^{x} = 40

Divide both sides by

62

1 0^{x} = \frac{20}{31}

Apply exponent rules

x ln (10) = ln (\frac{20}{31})

Solve

x ln (10) = ln (\frac{20}{31}) : x = \frac{ln ( \frac{20}{31} )}{ln ( 10 )}

x = \frac{ln ( \frac{20}{31} )}{ln ( 10 )}

7 e^{3 n - 5} + 5 = - 89

x^{2 x} = (2 x)^{x}

4^{x + 2} = 6^{- 2 x - 3}

e^{2 x} - 3 e^{x} = 10

6^{3 x + 1} = 777 6^{2}

What is the answer to 62*10^x=40 ?
The answer to 62*10^x=40 is x=(ln(20/31))/(ln(10))
Solve for x: 62*10^x=40
The solution is x=(ln(20/31))/(ln(10))