What is the answer to 25^x+5^{1+2x}=50 ?

The answer to 25^x+5^{1+2x}=50 is x=(ln(25/3))/(2ln(5))

Solve for x: 25^x+5^{1+2x}=50

The solution is x=(ln(25/3))/(2ln(5))

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2 5^{x} + 5^{1 + 2 x} = 50

x = \frac{ln ( \frac{25}{3} )}{2 ln ( 5 )}

Decimal Notation

x = 0.65869 \dots

Solution steps

2 5^{x} + 5^{1 + 2 x} = 50

Apply exponent rules

2 x ln (5) = ln (\frac{25}{3})

Solve

2 x ln (5) = ln (\frac{25}{3}) : x = \frac{ln ( \frac{25}{3} )}{2 ln ( 5 )}

x = \frac{ln ( \frac{25}{3} )}{2 ln ( 5 )}

- 4 e^{- 4 x} = \frac{e ^{- 12} - 1}{3}

5^{x - 4} = 25

5^{x} - \frac{1}{5 ^{x - 2}} = 24

1 0^{6 x} = 3^{3 x + 4}

6^{x} = 60

What is the answer to 25^x+5^{1+2x}=50 ?
The answer to 25^x+5^{1+2x}=50 is x=(ln(25/3))/(2ln(5))
Solve for x: 25^x+5^{1+2x}=50
The solution is x=(ln(25/3))/(2ln(5))