What is the answer to 3^x\times 5^{2x}=150 ?

The answer to 3^x\times 5^{2x}=150 is x=(ln(150))/(ln(75))

Solve for x: 3^x\times 5^{2x}=150

The solution is x=(ln(150))/(ln(75))

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3^{x} \cdot 5^{2 x} = 150

x = \frac{ln ( 150 )}{ln ( 75 )}

Decimal Notation

x = 1.16054 \dots

Solution steps

3^{x} \cdot 5^{2 x} = 150

Apply exponent rules

(x + lo g_{3} (5) \cdot 2 x) ln (3) = ln (150)

Solve

(x + lo g_{3} (5) \cdot 2 x) ln (3) = ln (150) : x = \frac{ln ( 150 )}{ln ( 75 )}

x = \frac{ln ( 150 )}{ln ( 75 )}

4^{x + 2} - 4^{x} = 120

15 - e^{x - 8} = 4

x^{x^{49}} = 7^{7^{5}}

e^{- x} + e^{- 2 x} = \frac{2}{3}

What is the answer to 3^x\times 5^{2x}=150 ?
The answer to 3^x\times 5^{2x}=150 is x=(ln(150))/(ln(75))
Solve for x: 3^x\times 5^{2x}=150
The solution is x=(ln(150))/(ln(75))