What are the solutions to the equation 3x^2-6x+3=3 ?

The solutions to the equation 3x^2-6x+3=3 are x=2,x=0

Find the zeros of 3x^2-6x+3=3

The zeros of 3x^2-6x+3=3 are x=2,x=0

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3 x^{2} - 6 x + 3 = 3

x = 2, x = 0

Solution steps

3 x^{2} - 6 x + 3 = 3

Move

3

to the left side

3 x^{2} - 6 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 3 \cdot 0}{2 \cdot 3}

(- 6)^{2} - 4 \cdot 3 \cdot 0 = 6

x_{1, 2} = \frac{- ( - 6 ) \pm 6}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 6}{2 \cdot 3}, x_{2} = \frac{- ( - 6 ) - 6}{2 \cdot 3}

x = \frac{- ( - 6 ) + 6}{2 \cdot 3} : 2

x = \frac{- ( - 6 ) - 6}{2 \cdot 3} : 0

The solutions to the quadratic equation are:

x = 2, x = 0

- 6 \leq \frac{3 - 2 x}{2} \leq 1

(1 - i)^{8}

27

\frac{1}{2} \cdot 4^{2}

50 y^{2} b + 25 y^{2} - 18 b - 9

What are the solutions to the equation 3x^2-6x+3=3 ?
The solutions to the equation 3x^2-6x+3=3 are x=2,x=0
Find the zeros of 3x^2-6x+3=3
The zeros of 3x^2-6x+3=3 are x=2,x=0