What is the answer to 10^x=121 ?

The answer to 10^x=121 is x=(2ln(11))/(ln(10))

Solve for x: 10^x=121

The solution is x=(2ln(11))/(ln(10))

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1 0^{x} = 121

x = \frac{2 ln ( 11 )}{ln ( 10 )}

Decimal Notation

x = 2.08278 \dots

Solution steps

1 0^{x} = 121

Apply exponent rules

x ln (10) = ln (121)

Solve

x ln (10) = ln (121) : x = \frac{2 ln ( 11 )}{ln ( 10 )}

x = \frac{2 ln ( 11 )}{ln ( 10 )}

x^{2} e^{x} + 2 x e^{x} = 0

6^{- 2 x} = 6^{3}

3 8^{x} = 65536

e^{x + 1} = 2^{x}

19450000 = 975 (1.76)^{x}